Two numbers have a difference of 8 what is the minimum product of these numbers

-16 (assuming you are allowed both positive and negative numbers)

Step-by-step explanation:

If you use two negative numbers, the result will be a positive, so the only way to get a number below zero is to use one positive and one negative number.

Here's the only options that provide one negative and one positive number:

1 x -7 = -7

2 x -6 = -12

3 x -5 = -15

4 x -4 = -16

5 x -3 = -15

6 x -2 = -12

7 x -1 = -7

Therefore, -16 is the lowest possible product of two numbers with a difference of 8

La forma estándar de una ecuación de un círculo es% 28x-h% 29% 5E2 +% 2B +% 28y-k% 29% 5E2 + = + r% 5E2

donde Pt (h, k) es el centro y r es el radio

x ^ 2 + y ^ 2-10x + 4y + 4 = 0

completando los cuadrados para ponerlos en la forma estándar

x ^ 2 -10x + y ^ 2 + 4y + 4 = 0

(x-5) ^ 2-25 + (y +2) ^ 2-4 + 4 = 0

 (x-5) ^ 2 + (y + 2) ^ 2 = 25

El centro es (5, -2) radio = 5