Two ships leave a harbor at the same time. One ship travels on a bearing S10°W at 14 miles per hour. The other ship travels on a bearing N75°E at 8 miles per hour. How far apart will the ships be after 2 hours?

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Ответ:

therealdest

09.11.2020

Mathematics

Number of small boxes shipped = 10

Number of large boxes shipped = 12

Step-by-step explanation:

Let x be the number of small boxes

and

y be the number of large boxes

According to the first statement, a total of 22 boxes were shipped

Equation 1 will be:

x+y=22

And

According to 2nd statement, Total weight was 1350 and we know the weight of one small box is 45 and large box is 75

So equation 2 will be:

45x+75y=1350

We will use the substitution method for solving the equation

So from equation 1

$x+y=22\\x=22-y$

Putting the value of x in eqn 2

$45x+75y=1350\\45(22-y)+75y=1350\\990-45y+75y=1350\\-45y+75y=1350-990\\30y=360\\\frac{30y}{30}=\frac{360}{30}\\y=12$

Putting the value of y in eqn 1

$x+y=22\\x+12=22\\x=22-12\\x=10$

So,

Number of small boxes shipped = 10

Number of large boxes shipped = 12 ..

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Two ships leave a harbor at the same time. One ship travels on a bearing S10°W at 14 miles per hour. The other ship travels on a bearing N75°E at 8 miles per hour. How far apart will the ships be after 2 ​hours?