Two square pyramids have the same volume. for the first pyramid, the side length of the base is 16in., and the height is 28 in. the second pyramid has a height of 112 in. what is the side length of the base of the second pyramids?

The volume of the pyramid is:
 V = ((Ab) * (h)) / 3
 Where,
 Ab: base area
 h: height
 Substituting values we have:
 First pyramid:
 V1 = ((16 * 16) * (28)) / 3
 V1 = 2389.333333 in ^ 3
 Second pyramid:
 2389.333333 = (L ^ 2 * (112)) / 3
 Clearing L we have:
 L = root ((2389.333333) * (3/112))
 L = 8 in
 
 The side length of the base of the second pyramids is:
 L = 8 in

if I’m correct the answer is $0.38

Step-by-step explanation: