Two systems of equations are shown. The first equation in system B is the original equation in system A. The second equation in system B is the sum of that equation and a multiple of the second equation in system A.

What is the solution to both systems A and B?
(3, 4)
(3, 5)
(4, 3)
(5, 3)

0.5 < x < 3

or (0.5, 3)

Step-by-step explanation:

-16t² + 56t + 2 = 26

Subtract both sides by 26

-16t² + 56t + 2 = 26

                 -26   -26

-16t² + 56t - 24 = 0

Divide both sides by -8 to simplify

(-16t² + 56t - 24)/8 = 0/8

2t² - 7t + 3 = 0

Factor

(x - 3)(2x - 1) = 0

Do this to find the x's

x - 3 = 0

 + 3  +3

x = 3

2x - 1 = 0

    + 1  + 1

2x = 1

2x/2 = 1/2

x = 0.5

0.5 < x < 3

This means the intervals will have to be between 0.5 and 3 seconds