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billyeyelash
02.12.2020 •
Mathematics
Una casa de dos plantas esta construida en un terreno rectangular de 66m² , tal como lo muestra los siguientes pasos si x es el frente de la casa y x+5 el largo. De la ecuacion cuadratica que define el area del terreno es x² + 5x-66=0 ¿Cuanto mide el frente de la casa?
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Ответ:
El frente de la casa es 6 metros.
Step-by-step explanation:
El area de la casa está dada por el área de un rectángulo:
En donde f es el frente = x , l es el largo = x+5 y A es el área = 66m²
Si la ecuación cuadrática que define el área del terreno viene dado por:
Resolviendo la ecuación cuadrática para x tenemos:
x₁ = -11 y x₂ = 6
Tomando el valor positivo, podemos decir que el frente de la casa es 6 metros.
Espero que te sea de utilidad!
Ответ:
Step-by-step explanation:
Since the triangles are equivalent,
3x - 2 = 5
Solve for x.
3x = 7
x = 7/3