babas97
20.06.2019 •
Mathematics
Use continuity to evaluate the limit. lim x→16 20 + x 20 + x step 1 consider the intervals for which the numerator and the denominator are continuous. the numerator 20 + x is continuous on the interval the denominator 20 + x is continuous and nonzero on the interval
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Ответ:
= 1
Step-by-step explanation:
We are given the expression, .
Since, we have that,
The numerator and denominator is (20+x), which is a polynomial is continuous for all the real numbers i.e. for all x belonging to .
Thus, the limit exists and is given by,
= = = 1.
So, = 1.
Ответ:
us court of appeals for the 11th circuit