natekotterman
25.09.2019 •
Mathematics
Use de moivre's theorem to express cos 5θ and sin 5θ in terms of sin θ and cos θ.
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Ответ:
(cosθ+isinθ)^n=cos(nθ)+isin(nθ)
Therefore,
R((cosθ+isinθ)^5)=cos(5θ)I((cosθ+isinθ)^5)=sin(5θ)
Simplifying,
cos^5(θ)−10(sin^2(θ))(cos^3(θ))+5(sin^4(θ))(cosθ)=cos(5θ)
Ответ:
3467 m
Step-by-step explanation: