zandariouslee
05.12.2019 •
Mathematics
Use implicit differentiation to find an equation of the tangent line to the curve at the given point.
x^2 + y^2 = (3x^2 + 4y^2 ? x)^2
(0, 0.25)
(cardioid)
y=?
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Ответ:
y = 2(x - 1/4)
Step-by-step explanation:
To find an equation of the tangent to a given curve, we need two vital information; one is the slope of the tangent (SOP) and the other is the point of tangency (POT).
to find the slope of tangent i will use the implicit differentiation to find the slope then apply the point given
so, first, the slope using implicit differentiation;
f(x) =
f'(x) = {tex}2x + 2y dy/dx = 2(3x^{2} + 4y^{2} - x)(6x + 8y dy/dx - 1){/tex}
applying the co-ordinates given; x = 0 and y = 1/4
SOP 2(0) + 2(1/4) dy/dx = 2[3(0)^2 + 4(1/4)^2 - 0][6(0) + 8(1/4) dy/dx - 1)
1/2 dy/dx = 2[4(1/16)][(8/4) dy/dx - 1]
1/2 dy/dx = 2[1/2][2 dy/dx - 1]
1/2 dy/dx = 2 dy/dx - 1
putting the dy/dx together
1 = 2 dy/dx - 1/2 dy/dx
1 = dy/dx (2 - 1/2)
make dy/dx subject
1 / 1/2 = dy/dx
therefore SOP = 2
POT
f(x) = (0)^2 + (1/4)^2 = [3(0)^2 + 4(1/4)^2 - 0]^2
1/16 = [4(1/16)]^2
1/16 = (1/4)^2
1/16 = 1/16
y = 0
using the slope formula
m = y - y2/ x - x2
2 = y - 0/ x - 1/4
y = 2(x - 1/4)
Ответ:
Hello from MrBillDoesMath!
C)
Discussion:
To solve x^2 = 36/81 take the square root of both sides.
x = square root of (36/81)
As 36 = 6*6 and 81 = 9*9,
x = square root of (6*6)/ (9.9) or 6/9
But 6 and 9 share the common factor "3" so
x = 6/9 = (2*3)/(3*3) = 2/3
The last equality was gotten by cancelling the common factor 3.
Regards, MrB