imran2k13
15.07.2019 •
Mathematics
Use technology and the given confidence level and sample data to find the confidence interval for the population mean muμ. assume that the population does not exhibit a normal distribution. weight lost on a diet: weight lost on a diet: 99 % confidence 99% confidence n equals 61n=61 x overbar equals 2.0 kgx=2.0 kg s equals 4.8 kg
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Ответ:
The given in this problem are:
99% confidence level
N = 61
Mean = 2.0 kg
Standard deviation = 4.8
Z value for a 9% confidence interval is 2.576
Confidence Interval = mean ± Z s/ sqrt n
= 2.0 ± 2.576(4.8/sqrt 61)
=2.0 ± 2.576 (0.6145770236779006736364371988794)
= 2.0 ± 1.5832
= 0.4168 < x < 3.5832
Ответ:
780 divided by 15 = 52
so therefore 52/60 = 13/15