Mathematics: Use technology to construct the confidence intervals for the population variance sigmaσsquared2 and the population standard deviation sigmaσ. assume the sample is taken from a normally distributed population.cequals=0.99, sequals=35, nequals=19the confidence interval for the population variance is ( nothing, nothing).

90,000the reason is because look at the 1,000 place that rounds the 10,000 place to 0 and carries the 1 over to the 100,000 place...

Use technology to construct the confidence intervals

alonnachambon

09.01.2022

(593.44, 3519.67).

Step-by-step explanation:

As per given , we have

Confidence level : $1-\alpha=0.99$

Significance level : $\alpha=0.01$

Sample size : n= 19

Sample standard deviation : s= 35

Using chi-square distribution table , the critical values are:

$\chi^2_{\alpha/2, n-1}=\chi^2_{0.005, 18}=37.1565\\\\\chi^2_{1-\alpha/2, n-1}=\chi^2_{0.995, 18}=6.2648$

Now, the Confidence interval for the population variance is given by :-

$\dfrac{(n-1)s^2}{\chi^2_{\alpha/2, n-1}}$

Hence, the confidence interval for the population variance is (593.44, 3519.67).

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