Use the distance formula to determine the distance

Ответ:

tata64

15.01.2022

For points (x1,y1) and (x2,y2)
D= $\sqrt{(x2-x1)^2+(y2-y1)^2}$

(-5,5)
(1,-3)
(x,y)
x1=-5
y1=5
x2=1
y2=-3

D= $\sqrt{(x2-x1)^2+(y2-y1)^2}$
D= $\sqrt{(1-(-5))^2+(-3-5)^2}$
D= $\sqrt{(6)^2+(-8)^2}$
D= $\sqrt{36+64}$
D= $\sqrt{100}$
D=10

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Ответ:

nathaniel12

05.10.2021

Mathematics

If i drew it correctly, then al would also equal 14 in., because the midsegment divides the line ab into 2, equal in length lines.therefore, al = lb

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Use the distance formula to determine the distance points (-5,5) and (1,-3)

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