Use the elimination method to solve the following system of equations: 2x+y=3
3x – y= 12
The solution is

x = 3

y = -3

(3, -3)

Step-by-step explanation:

Choose one of the equations and isolate y. I will use the first one.

2x + y = 3

Y = 3 - 2x

Now sub the solution for y into the equation below.

3x - y = 3

3x - (3 - 2x) = 12

3x - 3 + 2x = 12

5x - 3 = 12

5x = 15

x = 3

To get y, sub the answer for x into one of the equations.

2(3) + y = 3

6 + y = 3

y = 3 - 6

y = -3

(x,)y) =(3,-3)

Step-by-step explanation:

add the equations vertically to eliminate one variable

2x +y = 3

3x -y = 12

5x =15    divide both sides by 5

x  = 3       now substitute the given value of x into the equation  2x+y=3

2 x 3 + y = 3  multiply 2x3

6 +y =3           move constant to the right

y = 3-6

y = -3  

blank 1:5.00 blank 2:15.00

Step-by-step explanation:

1%10x50=50% =5$

10+5=15