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fatty18
08.10.2019 •
Mathematics
Use the given values of nequals=93 and pequals=0.24 to find the maximum value that is significantly low, muμminus−2sigmaσ, and the minimum value that is significantly high, muμplus+2sigmaσ. round your answer to the nearest hundredth unless otherwise noted.
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Ответ:
The maximum value that is significantly low is 14.0828
The minimum value that is significantly high is 30.5572
Step-by-step explanation:
If we assume a binomial distribution, n is equal to 93 and p is equal to 0.24, the mean μ and the standard deviation σ are calculated as:
μ = n*p = 93*0.24 = 22.32
σ =![\sqrt{n*p*(1-p)} =\sqrt{93*0.24*(1-0.24)} =4.1186](/tpl/images/0299/3225/56677.png)
Then, the maximum value that is significantly low, μ−2σ, and the minimum value that is significantly high, μ+2σ, are equal to:
μ − 2σ = 22.32 - 2(4.1186) = 14.0828
μ + 2σ = 22.32 + 2(4.1186) = 30.5572
Ответ:
2,400 notebooks ÷ 3 days = 800.
800 notebooks × 11 days = 8,800