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exoticbunnylover123
19.10.2019 •
Mathematics
Use the law of sines to solve the triangle b=31, c=104, a=3(5/8)m
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Ответ:
if ∠C = 104 + ∠B = 31, therefore ∠A = 45 (A + B + C = 180)
Sin45 / 3 5/8 = Sin31 / b (multiply both sides by b)
bSin45 / 3 5/8 = Sin31 (multiply both sides by 3 5/8)
bSin45 = 3 5/8Sin31 (divide by Sin45)
b = 3.625Sin31 / sin45
b = 2.64
Sin45 / 3 5/8 = Sin104 / c (multiply by c)
cSin45 / 3 5/8 = Sin104 (multiply both sides by 3 5/8)
cSin45 = 3 5/8Sin104 (divide by Sin45)
c = 3.62Sin104 / Sin45
c = 4.97
A = 45
b = 2.64
c = 4.97
Ответ: