Use the table to identify values of p and q that can be used to factor x2 + x – 12 as (x + p)(x + q). a. –2 and 6 b. 3 and –4 c. –3 and 4 d. 2 and –6

For this case we have the following polynomial:
 x2 + x - 12
 Factoring we have:
 (x-3) (x + 4)
 We note that the polynomial is written as:
 (x + p) (x + q)
 Thus,
 p = -3
 q = 4
 
 The values of p and q that can be used to factor x2 + x - 12 as (x + p) (x + q) are:
 C. -3 and 4

Answer is c you subtract the difference big by small