kingzae5
26.10.2019 •
Mathematics
Use these values to solve this problem. x=2,y=3,z=4. 21xy/x+z
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Ответ:
21xy/x+z
Substitute x with 12, y with 3, z with 4
21xy/x+z
=21(2)(3)/(2+4)
=42(3)/16
=126/16
=21. As a result, 21 is your correct answer. Hope it help!
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