Using ABC, identify the ratio for sine of C

BA / AC

Step-by-step explanation:

Given the triangle ABC;

To obtain the Sin C

Defining the attached triangle with respect to C:

Sine = opposite / hypotenus

Sin C = BA / AC

Hence, the ratio of sinC is BA /AC

I'm pretty sure its y = x^2 + 5x + 20

Step-by-step explanation:

This is because i added them (or combined)

Like this

x^2 + 2x

+ 3x + 20

x^2 + 5x + 20

Please Correct Me If I Am Wrong Okay love.

Again sorry if i'm wrong.

I'm pretty sure i'm not.