Using the image below, find the x value for the point that divides the line segment CD into a ratio of 4:1. (4 points) Segment CD is shown. C is at 9, 6 and D is at 5, 1.

3
5.8
2
6.2

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Ответ:

hollisjune3047

31.05.2020

Mathematics

The watered area is approximately 3783 square feet.

Step-by-step explanation:

The area that is watered due to the rotation of the spankler is a circular section area (), whose formula is:

$A = \frac{\theta }{2}\times \frac{1}{360^{\circ}}\times 2\pi \times d^{2}$

Where:

- Water distance, measured in feet.

$\theta$ - Rotation angle, measured in sexagesimal degrees.

Given that $d = 85\,ft$ and $\theta = 60^{\circ}$ , the watered area is:

$A = \frac{60^{\circ}}{2} \times \frac{1}{360^{\circ}}\times 2\pi \times (85\,ft)^{2}$

$A \approx 3783\,ft^{2}$

The watered area is approximately 3783 square feet.

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Using the image below, find the x value for the point that divides the line segment CD into a ratio of 4:1. (4 points) Segment CD is shown. C is at 9, 6 and D is at 5, 1. 3 5.8 2 6.2