Using the slope intercept form of a line find the equation of a line with a slope of 4/3 in a y intercept of negative one. then graph the line on the grid provided in explain how you determine your graph

Hello:

equation is the line is : y = ax+b        a is a slope

y = (4/3)x+b

passing through the point (0;−1) :   -1 =(4/3)(0)+b   so : b = -1

y = (4/3)x-1

you can determine your graph by the point (0 ; -1) and another point ( 3/4 ; 0)

for exempl  when y = 0    you have :  (4/3)x-1 = 0  so :  x = 3/4

1 y = -11

2 x =0

3 x= 2

4 y= 21

5 x= 8

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