shanewugden7362
27.07.2019 •
Mathematics
Với điều kiện nào của m thì phương trình ( 3m^2 - 4) x -1=m-x có nghiệm duy nhất?
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Ответ:
giải bpt mới tìm được đó ta đc : m ≤ -3 hoặc m ≥ 1
b, * Xét m-1=0 <=> m=1 => thay m=1 vào pt thì pt có 1 nghiệm là 1/8 (1)
* Xét m-1 ≠ 0 <=> m ≠ 1
=> pt có nghiệm khi denta' ≥ <=> (m+3)^2 - (m-1)(-m+2) ≥0 <=> 2m^2 +3m+11 ≥ 0 (*)
-> bpt (*) có denta < 0 nên nó luôn đúng với mọi m ≠1 -> denta của pt đã cho luôn > 0 với mọi m ≠ 1 (2)
từ (1) (2) => với mọi m pt luôn có nghiệm
Ответ:
The Pythagorean Theorem is:
a² + b² = c²
We have b = 48 and c = 50
Remember: The hypotenuse is always longer.
a² + 48² = 50²
a² + 2304 = 2500
a² = 2500 - 2304
a² = 196
a = √196
a = 14
The missing length is 14.
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