VERY IMPORTANT WILL GIVE ANSEWER CORRECTLY using Radicals and Exponents
3. Yuma’s population at the end of 2017 was 29,472, and its growth rate has been 1.42% each year. Jacob lives in Yuma and wants to track the predicted population growth over time for an experiment.
a. Write an equation to model the population growth of Yuma.
b. What was the population in June of 2018? Round your answer to the nearest integer.
c. What was the population at the end of 2018? Round your answer to the neatest integer.
d. What will the population be in 2025? Round your answer to the nearest integer.

Answers:

(a) the population function is exponential in the number of years (t) after 2017:

N(t)=29472•1.0142^t

(b) Although the model is defined on a yearly basis, we can answer the question by calculating the projected population at the end of 2018 (t=1) and, under the assumption of same birth rate every month, take half of the yearly increase (end of June):

N(1) = 29890.50

June population: 29681

(c) N(1) = 29891 (see (b) above)

(d) Population in 2025 is the function value at t=2025-2017=8

N(8)=29472•1.0142^8=32991.22... ≈32991

Step-by-step explanation:

If the whole length of DEF is given as 7, and segment DE is 2, then segment EF is 7 - 2 = 5