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bibhu42kumarp7o4ss
25.03.2020 •
Mathematics
VThe Mathematics Club will select a president, a vice president, and a treasurer for the club. If there are 15 members in the club, how many different selections of a president, a vice president, and a treasurer are possible if each club member can be selected to only one position?
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Ответ:
2730 different selections
Step-by-step explanation:
This problem is solved using permutations: it is similar to combination, but the order of each element matters (if person A is president, person B is vice and person C is treasurer, this is a different case from a case where person A is vice, person B is treasurer and person C is president)
The formula of permutation is:
P = n!/(n-p)!
where n is the total number of members in this case (15), and p is the number of different positions (3).
So, the number of different selections is:
P = 15!/12! = 15*14*13 = 2730 different selections
Ответ:
1,2 & 4
Step-by-step explanation:
Just took the test