eddou55
30.07.2021 •
Mathematics
We are given a jar full of thousands of red and blue marbles. We want to estimate the unknown proportion pof red marbles in the jar. To do this, we randomly draw 100 marbles and count reds: it so happens we drew 45 reds. Enter values in decimal form, rounded to four decimal places (or more).
We estimate the proportion of reds in the jar to be
Attach a give-or-take value to this estimate. (That is, estimate the standard error.)
For a 96% confidence interval, about how many standard errors should be added to and subtracted from the estimate?
Set up an approximate 96% confidence interval for the unknown proportion of reds in the jar.
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Ответ:
(0.3478, 0.5522)
Step-by-step explanation:
Given:
Total number of red marbles, x = 45
Total number of marbles, n = 100
Phat = x / n = 45 / 100 = 0.45
The confidence interval, C.I is given by :
Phat ± Zcritical * standard error
Phat ± Zcritical * √Phat(1 - Phat) / n
Zcritical at 96% = 2.0537
The standard error = √Phat(1 - Phat) / n
S.E = √(0.45 * 0.55) / 100 = 0.0497493
C.I = 0.45 ± (2.0537 * 0.0497493)
C.I = 0.45 ± 0.10217013741
C. I = (0.3478, 0.5522)
Ответ:
n = 3p
Step-by-step explanation:
to solve this, you need to get n by itself.
3n - 5p + 2n = 10p
+5p +5p
3n + 2n = 15p
5n = 15p
5n/5 = 15p/5
n = 3p
hope it helps!