Mathematics: We are standing on the top of a 128 feet tall building and launch a small object upward. The object s vertical position, measured in feet, after t seconds is h ( t ) = − 16 t 2 + 32 t + 128 . What is the highest point that the object reaches?

We are standing on the top of a 128 feet tall - id1285441728, delincuent5641

mckinleesmomp6qj1e

20.01.2022

h(t) = -16 $t^{2}$ + 32t + 128

h(t) = 128 feet

128 = -16 $t^{2}$ + 32t + 128

-16 $t^{2}$ + 32t + 128 - 128 = 0

-16 $t^{2}$ + 32t =

-16 $t^{2}$ = - 32t

divide through by 16t

-16 $t^{2}$ / 16t = -32t/16t

t = 2

t = 2 seconds

Step-by-step explanation:

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villatoroo84502

17.09.2022

Yes

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