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savannahwonder
savannahwonder
20.10.2021 • 
Mathematics

We have a binomial experiment with n = 18 trials, each with probability p = 0.15 of a success. A success occurs if a student withdraws from a class, so the number of successes, x, will take on the values 0, 1, and 2. The probability of each x value, denoted f(x), can be found using a table like the one below. Note that these values are rounded to four decimal places.
nx p
0.100.15 0.200.25
1800.15010.05360.01800.0056
10.30020.17040.08110.0338
20.28350.25560.17230.0958
30.16800.24060.22970.1704
40.07000.15920.21530.2130
50.02180.07870.15070.1988
For an experiment with n = 18 trials, the probability of exactly x = 0 successes where the probability of a success on a trial is p = 0.15 can be found by going along the row for x = 0 within the n = 18 grouping until you get to the column for p = 0.15. Doing so gives f(0) = .
Use the above table to find the probabilities for x = 1 success, f(1), and x = 2 successes, f(2).
f(1)=
f(2)=

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