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savid88061
13.04.2021 •
Mathematics
We measure the diameters for a random sample of 25 oak trees in a neighbourhood. Diameters of oak trees in the neighbourhood follow a normal distribution with standard deviation 8.25 cm. A confidence interval for the true mean diameter of all oak trees in the neighbourhood is calculated to be (36.191, 42.969). What is the confidence level of this interval
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Ответ:
The required confidence inteval = 94.9%.
Step-by-step explanation:
Confidence interval: Mean ± Margin of error
Given: A confidence interval for the true mean diameter of all oak trees in the neighbourhood is calculated to be (36.191, 42.969).
i.e. Mean + Margin of error = 42.969 (i)
Mean - Margin of error = 36.191 (ii)
Adding (i) and (ii), we get
Margin of error = 42.969-39.58 [from (i)]
= 3.389
Margin of error =![t^* \dfrac{\sigma}{\sqrt{n}}](/tpl/images/1254/6863/2f72e.png)
here n= 25![, \ \sigma=8.25](/tpl/images/1254/6863/61f8c.png)
i.e.
Using excel function 1-TDIST.2T(2.054,24)
The required confidence inteval = 94.9%.
Ответ: