We want to find the zeros of this polynomial:
p(x) = (2x2 + 7x + 5)(x – 3)

  x = -5/2, -1, or 3

Step-by-step explanation:

The quadratic factor can be factored further to give ...

  p(x) = (2x +5)(x +1)(x -3)

The zeros of p(x) are the values of x that make the factors zero:

  2x +5 = 0   ⇒   x = -5/2

  x +1 = 0   ⇒   x = -1

  x -3 = 0   ⇒   x = 3

The zeros of the polynomial are x = -5/2, x = -1, or x = 3.