jasminevargasolea
13.06.2021 •
Mathematics
What are the center and radius of the circle defined by the equation x^2 + y^2 -6x + 8y + 21=0
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Ответ:
Step-by-step explanation:
(x²-6x)+(y²+8y)=-21
(x²-6x+9)+(y²+8y+16)=-21+9+16
(x-3)²+(y+4)²=4
center=(3,-4),radius=√4=2
Ответ:
y=2x+4
Step-by-step explanation: