Mathematics: What are the coordinates of point (x,y) on the terminal ray of angle

What are the coordinates of point (x,y) on the - id3190330, MichaelBoolin87241

Pattondestiny

06.01.2022

Option 1. (-5, 12)

Step-by-step explanation:

Here given values of the angles are csc∅ = 13/12 Or sin ∅ = 12/13

sec ∅ = -13/5 Or cos ∅ = -5/13

cot ∅ = -5/12 Or tan ∅ = -12/5

As we know cos ∅ = x-coordinates / y-coordinates which = negative value

tan ∅ = y-coordinates / x - coordinates = negative value

Now we can say the angle lies in second quadrant. So the point (x, y) will be (-5, 12).

Therefore answer is option 1.

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potatogirl9300

01.02.2022

Step-by-step explanation:

h(t) = (t + 3)² + 5

A) h(t) = (t + 3)² + 5 -2 ≤ t ≤ 0

average rate of change in h over the change in t is given as:

$\frac{h(0)-h(-2)}{0-(-2)}=\frac{(0+3)^2+5-[(-2+3)^2+5]}{0+2}=\frac{14-6}{2} =4$

It does not have a negative average rate of change

B) A) h(t) = (t + 3)² + 5 -4 ≤ t ≤ -3

average rate of change in h over the change in t is given as:

$\frac{h(-3)-h(-4)}{-3-(-4)}=\frac{(-3+3)^2+5-[(-4+3)^2+5]}{-3+4}=\frac{5-6}{1} =-1$

It have a negative average rate of change

c) A) h(t) = (t + 3)² + 5 -3 ≤ t ≤ 4

average rate of change in h over the change in t is given as:

$\frac{h(4)-h(-3)}{4-(-3)}=\frac{(4+3)^2+5-[(-3+3)^2+5]}{4+3}=\frac{54-5}{7} =7$

It does not have a negative average rate of change

D) h(t) = (t + 3)² + 5 1 ≤ t ≤ 4

average rate of change in h over the change in t is given as:

$\frac{h(4)-h(1)}{4-(1)}=\frac{(4+3)^2+5-[(1+3)^2+5]}{4-1}=\frac{54-21}{3} =11$

It does not have a negative average rate of change

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