Reese7977
04.07.2019 •
Mathematics
What are the dimensions of a 72in television with a 16: 9 aspect ratio
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Ответ:
Height is 35.3 inches.
Width is 62.8 inches.
Dimensions are 62.8 by 35.3.
Step-by-step explanation:
We can solve this problem using some simple trigonometry.
First, we need to calculate the angle of the corner to corner line relative to the base. We use tan⁻¹ to solve for this.
tan⁻¹()
29.35775354°
We can now use this angle to find the side length to hypotenuse ratios. First, we will find the height using sine.
sin is
= sin(29.35775354°) --- plug in known info
= 0.4902612396 --- solve
x = 0.4902612396 × 72 --- multiply both sides by 72
x = 35.29880925
Height is 35.3 inches.
Now, we can solve for the width using cosine.
cos is
= cos(29.35775354°) --- plug in known info
= 0.8715755371 --- solve
w = 0.8715755371 × 72 --- multiply both sides by 72
w = 62.75343867
w = 62.8 inches
Ответ:
11:22 AM
Step-by-step explanation:
By means of a statement we can know that:
After an hour and 8 minutes, he stays 8 minutes behind
Which means that in 2 hours, it will take 16 minutes
If it is 10:30, it means that it is 6:30 hours later, that is to say 6.5.
therefore 6.5 x 8 = 52
Which means that at 10:30 the clock is 52 minutes late
So the correct time is 11:22 AM