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adrian540
01.09.2019 •
Mathematics
What are the domain, range, and asymptote of h(x) = 2x + 4? domain: {x | x > 0}; range: {y | y is a real number}; asymptote: y = 0 domain: {x | x > –4}; range: {y | y is a real number}; asymptote: y = –4 domain: {x | x is a real number}; range: {y | y > 0}; asymptote: y = 0 domain: {x | x is a real number}; range: {y | y > 0}; asymptote: y = –4
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Ответ:
Option 3 is correct.
y=0 is the asymptote.
Step-by-step explanation:
Given : The function![h(x) = 2^{x + 4}](/tpl/images/0217/3705/87d22.png)
To find : The domain, range, and asymptote of the given function.
Solution :
The given function
is an exponential function.
Domain is where the function is defined.
Therefore,![D=(-\infty,\infty)[x|x\in {R}]](/tpl/images/0217/3705/c3042.png)
The range is the set of values that correspond with the domain.
At x tends to
function tends to zero.
At x tends to
function tends to ![\infty](/tpl/images/0217/3705/4d9a7.png)
Therefore,![R=(0,\infty)[y|y0]](/tpl/images/0217/3705/ead7d.png)
Exponential functions have a horizontal asymptote.
The equation of the horizontal asymptote is y=0.
Therefore, Option 3 is correct.
Ответ:
Consider the function
First, note that parent function
has
the domainThe graph of the function
can be obtained from the parent function using translation 4 units to the left. This translation doesn't change the domain, the range and the asymptote of the parent function.
correct choice is C
Ответ:
22.78 to 2dp
Step-by-step explanation:
91.10 euros divide by 4 =22.775
=22.78 to 2dp