What are the foci of the hyperbola whose equation

Ответ:

steve12335

24.01.2022

The foci of the hyperbola is (0,3) and (0,-3).

Step-by-step explanation:

Given,

The equation of the hyperbola: $\frac{(x-6)^{2} }{16} -\frac{(y+7)^{2} }{9} =1$

To find the foci of the given parabola

Formula

If the equation of the hyperbola: $\frac{(x-h)^{2} }{a^{2} } -\frac{(y-k)^{2} }{b^{2} } =1$

The focus will be (0,±c) where c² = a²+b²

Now,

Here, a=3 and b=4

c² = 3²+4² = 25

or, c = ±5

Hence,

The foci of the hyperbola is (0,3) and (0,-3)

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