What are the next geometric sequences? the calculator won’t seem to give right answers

5. the numbers are being multiplied by 4 each time, so the geometric sequence would be

an= 1/2(4) ^(n-1)

6. the numbers are being multiplied by 1/4 each time, so the geometric sequence would be

an= 32(1/4)^(n-1)

an in the formula is what ever term in the sequence.
32 or 1/2 is the a which is the first term in the sequence.
4 or 1/4 is the r in the sequence because it is the common ratio so what the equation was multiplied by to get the next term.
(n-1) is because when you are using this equation to solve for whatever term (an) you must subtract the first number in the sequence to get an accurate number

an you can input whatever number when trying to solve.

a) (μ) = $128

b) 0.9472

c)  0.6671

Step-by-step explanation:

Given that:

Allegiant Airlines charges a mean base fare of $89.

this implies that: mean base fare = $89.

The question proceeds by stating the additional charge on  its website, checking bags, and inflight beverages.

so , additional charges turns out to be = $39 per passenger

Now, Suppose a random sample of 60 passengers is taken

random sample (n) = 60

The population standard deviation of total flight cost is known to be $40

standard deviation (σ) = 40

Question (a) says; we should find the population mean cost per flight

To determine that; we have to consider the total sum(μ) of the mean base fare with the mean additional charges.

Population mean cost per flight (μ)  =  mean base fare + mean additional charges

(μ) = $89 + $39

(μ) = $128

b)

What is the probability the sample mean will be within $10 of the population mean cost per flight (to 4 decimals)?

To determine that; we have:

P(128 - 10 ≤ Х ≤ 128 +10)

= P(118 ≤ Х ≤  138)

=               (where  =  μ  and ∝ = σ )

=

=

Using Excel Command to approach this process, we have;

= 0.9736 - 0.0264

= 0.9472     (to four decimal places)

∴ the probability that the sample mean will be within $10 of the population mean cost per flight = 0.9472

c)

What is the probability the sample mean will be within $5 of the population mean cost per flight (to 4 decimals)?

We wll have to go through the process like the one attempted above in question (b);

So;

P(128 - 5 ≤ Х ≤ 128 + 5)

= P(123 ≤ Х ≤  133)

=                           (where  =  μ  and ∝ = σ )

=

=

Computing these data in Excel; we have

= 0.8335 -0.1665

= 0.6671         (to 4 decimal places)

∴  the probability that the sample mean will be within $5 of the population mean cost per flight.