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mendezmarco2004
25.07.2019 •
Mathematics
What are the points of discontinuity? are they all removable? show your work. y= (5-x)/x^2-6x+5
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Ответ:
y = (5-x) / x ^ 2-6x + 5
Rewriting we have:
y = (5-x) / (x-5) * (x-1)
The discontinuity points are:
x = 5
x = 1
x = 5 is removable. For this, we rewrite the function again:
y = (-1 * (5-x)) / (- 1 * (x-5) * (x-1))
y = ((x-5)) / ((x-5) * (1-x))
We cancel similar terms:
y = 1 / (1-x)
the points of discontinuity are:
x = 5
x = 1
x = 5 is removable
Ответ:
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