Mathematics: What are the roots of the quadratic equation below? 3x^2+15x-5=0

Your motherStep-by-step explanation:...

What are the roots of the quadratic equation below?

mujithkalhan2762

10.07.2021

X1 = $\frac{=15+\sqrt{285} }{6}$ and X2 = $\frac{-15-\sqrt{285} }{6}$

Step-by-step explanation:

To find the roots of a quadratic equation, you need to solve the quadratic equation by using the quadratic formula.

You can use the (Equation/Function) mode on the calculator.

$\frac{-b+-\sqrt{b^{2} -4ac } }{2a} x \neq 0$

For this equation,

a = 3

b = 15

c = -5

X1 = $\frac{-15+\sqrt{15^{2} -4(3)(-5) } }{2(3)} x \neq 0$

X2 = $\frac{-15-\sqrt{15^{2} -4(3)(-5) } }{2(3)} x \neq 0$

Solving this on the calculator and you should get

X1 = $\frac{=15+\sqrt{285} }{6}$ X2 = $\frac{=15-\sqrt{285} }{6}$

a, b, c = constants, where a ≠ 0

x = the unknown

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