Mathematics: What are the solutions of 4x^2-x+9=0 ?

What are the solutions of 4x^2-x+9=0 ? - id42903829549, sophiateaches053

live4dramaoy0yf9

10.01.2022

The answer is A

$x=\frac{1+i\sqrt{143} }{8}$ and $x=\frac{1-i\sqrt{143} }{8}$

Step-by-step explanation:

∵ 4x² - x + 9 = 0 ⇒ is quadratic equation

∴ $x=\frac{-b+\sqrt{b^{2}-4ac } }{2a}$

∴ $x=\frac{-b-\sqrt{b^{2}-4ac } }{2a}$

Where a is the cooficient of x² , b is the cooficient of x and c is the numerical term

∵ a = 4 , b = -1 and c = 9

∴ $x=\frac{-(-1)+\sqrt{(-1)^{2}-4(4)(9) } }{2(4)} =\frac{1+\sqrt{1-144} }{8}$

$=\frac{1+\sqrt{-143} }{8}=\frac{1+i\sqrt{143} }{8}$ ⇒ i = √(-1)

∴ $x=\frac{1-i\sqrt{143} }{8}$

∴The solutions are:

x= $\frac{1+i\sqrt{143} }{8}$ and x= $\frac{1-i\sqrt{143} }{8}$

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tyrique86

19.04.2021

A, B, and D.

Step-by-step explanation:

Bias- prejudice in favor of or against one thing, person, or group compared with another, usually in a way considered to be unfair.

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