What are the solutions of the equation 6x2 +5x+1 = 0 ?

see explanation

Step-by-step explanation:

Given

6x² + 5x + 1 = 0

To factorise the quadratic

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term

The factors are + 3 and + 2

Use these factors to split the x- term

6x² + 3x + 2x + 1 = 0 ← ( factor the first/second and third/fourth terms )

3x(2x + 1) + 1 (2x + 1) = 0 ← factor out (2x + 1) from each term

(2x  1)(3x + 1) = 0

Equate each factor to zero and solve for x

2x + 1 = 0 ⇒ 2x = - 1 ⇒ x = -

3x + 1 = 0 ⇒ 3x = - 1 ⇒ x = -

h = 221.7 m

Step-by-step explanation:

It is given that,

An observer (O) is located 400 feet from a building (B). The observer notices a kite (K) flying at a 29° angle of elevation from his line of sight. We need to find how high is the kite flying over the building?

The attached figure shows the whole scenario. It means we need to find the value of h.

Using trigonometry as follows :

So, the bird is flying at a height of 221.7 m over the building.