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CHRONICxDJ
09.01.2020 •
Mathematics
What are the solutions of
-x^2+4x=x-4?
a. -5 and 0
b. -5 and -1
c. -1 and 4
d. 0 and 4
Solved
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Ответ:
times -1
x^2-4x=-x+4
add x to both sides and minus 4 from both sides
x^2-3x-4=0
factor
what 2 numbers multiply to get -4 and add to get -3?
-4 and 1
(x-4)(x+1)=0
set to zero
x-4=0
x=4
x+1=0
x=-1
-1 and 4
C is answer
Ответ:
-x^2 + 3x + 4 = 0
multiply through by -1:-
x^2 - 3x - 4 = 0
factoring:-
(x - 4)(x + 1) = 0
x = 4 and -1
C
Ответ:
-8a
or
3a - l^2a
Step-by-step explanation: