garcia36
18.03.2021 •
Mathematics
What are the solutions to the following equation: 6x ^2 - 13x + 6 = 0
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Ответ:
x2= 3/2
These are the answers
Ответ:
C . . . (18, -8)
The slope of the line AC is (-8 + 2) / (18 + 4) = -6 / 22 = -3/11 .
The slope of any line perpendicular to AC is 11/3 .
The midpoint of the line segment AC is [ 1/2(-4+18), 1/2(-2-8) ]
= (7, -5) .
Now you have the slope and one point on the
perpendicular bisector of AC .
Slope = 11/3
Point = (7, -5)