What are the zeroes of f(x) = x2 − 2x − 3?
x = −3, 1
x = −3, −1
x = 3, 1
x = 3, −1

Option 4th is correct

x = 3, -1

Step-by-step explanation:

Given the equation:

To find the zeroes of f(x).

Set f(x) = 0

then;

Factorize this equations:

Split the middle terms we have;

⇒

⇒

By zero product property we have;

x-3 = 0 and x+1 = 0

⇒x = 3 and x = -1

Therefore, the zeroes of the function f(x) are :

x = 3 and x = -1

Following the formula: Pn on n+1 vertices {v0, v1, v2, …, vn} With n>2 edges as vertices we know that the component is not a tree. At the same time we know it must contain a cycle. Therefore the size of the vertices is not possible to exceed 2n, and the degree of any vertex in any sub-graph has a minimal value of vn. Therefore the maxim is 2n and the minimum is vn.