tony4561
30.07.2019 •
Mathematics
What are the zeroes of the function? what are their multiplicities? = x4 – 4x3 + 3x2 (1 point)
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Ответ:
You can simplify the terms as so:
x^2(x^2-4x+3) = 0
The equation above now contains x^2 and a quadratic function. A potential solution is x = 0 because x^2 = (0)^2 = 0.
Regarding the quadratic part of the equation,
x^2 - 4x + 3 = 0
(x+4)(x-1) = 0
When x = -4 or 1, the entire equation equals zero.
Therefore, the zeroes of the function are -4, 0, and 1.
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