What are the zeros of g(x)=(3x-1)(2x+5)(7x-14)^2
answer asap by the end of the day with the work. plz!

see explanation

Step-by-step explanation:

To find the zeros equate g(x) to zero, that is

(3x - 1)(2x + 5)(7x - 14)² = 0

Equate each factor to zero and solve for x

3x - 1 = 0 ⇒ 3x = 1 ⇒ x =

2x + 5 = 0 ⇒ 2x = - 5 ⇒ x = -

(7x - 14 )²  = 0 ⇒ 7x - 14 = 0 ⇒ x = 2 with multiplicity 2

they are, due to the fact that they are seperate items.

im guessing that there is an equal chance for all the colors and that its just as easy to get both or neither