Mathematics: What are the zeros of the function? f (x) = x^3 - x^2 - 6x a) -1, 0, and 3 b) -3, 0, and 1 c) -3, 0, and 2 d) -2, 0, and 3

x = 8Step-by-step explanation:The line segment inside the triangle is an angle bisector and divides the opposite side into segments that are proportional to the other 2 sides, that is = ( cross- multiply )6x(11x - 4) = 63x² ← distribute left side66x² - 24x = 63x² ( subtract 63x² from both sides )3x² - 24x = 0 ← factor out 3x from each term on the left side3x(x - 8) = 0Equate each factor to zero and solve for x3x = 0 ⇒ x = 0x - 8 = 0 ⇒ x = 8But x 0 , then x = 8...

What are the zeros of the function? f (x) = x^3

Ответ:

dylancasebere

01.06.2020

Mathematics

Try this explanation:
if to re-write the function f(x)=x(x²-x-6), then to make up the equation x(x²-x-6)=0, it is possible to find the zeros requred:
x(x-3)(x+2)=0, x=0;x=-2;x=3.

D -2;0;3

0,0(0 оценок)

Ответ:

cicilee49

15.02.2023

Mathematics

x = 8

Step-by-step explanation:

The line segment inside the triangle is an angle bisector and divides the opposite side into segments that are proportional to the other 2 sides, that is

$\frac{11x-4}{9x}$ = $\frac{7x}{6x}$ ( cross- multiply )

6x(11x - 4) = 63x² ← distribute left side

66x² - 24x = 63x² ( subtract 63x² from both sides )

3x² - 24x = 0 ← factor out 3x from each term on the left side

3x(x - 8) = 0

Equate each factor to zero and solve for x

3x = 0 ⇒ x = 0

x - 8 = 0 ⇒ x = 8

But x > 0 , then x = 8

0,0(0 оценок)

What are the zeros of the function? f (x) = x^3 - x^2 - 6x a) -1, 0, and 3 b) -3, 0, and 1 c) -3, 0, and 2 d) -2, 0, and 3

Ответ:

Ответ:

Ask your question to the AI advisor

More tips

Answers on questions: Mathematics

Ask an AI advisor a question