tigermath85
16.11.2019 •
Mathematics
What are the zeros of the quadratic function f(x) = 2x^2 + 16x – 9
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Ответ:
2x²+16x-9 = 0
Δ = 16²-4(2)(-9) = 256 +72 = 328
x = (-16+√328)/4
Ответ:
Explanation: