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ujusdied3912
01.01.2020 •
Mathematics
What are the zeros of the quadratic function f(x) = 6x² + 12x - 7?
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Ответ:
x = (-9 + 2i√6)/12 and (-9 - 2i√6)/12
Step-by-step explanation:
"Finding zeroes" means find the x-values that make f(x) = 0, so we have...
0 = 6x² + 12x - 7
Use quadratic equation to solve...
x = [-12 ± √(12² - 4(6)(-7))]/[2(6)]
x = [-12 ± √(144 + 168)]/12
x = [-9 ± √-24]/12
***√-24 becomes (√24)(√-1) which becomes (√4)(√6)(√-1),
√-1 = i, so this simplifies to 2i√6
x = [-9 ± 2i√6]/12
x = (-9 + 2i√6)/12 and (-9 - 2i√6)/12
Ответ:
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Step-by-step explanation:
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