Mathematics: What are the zeros of the quadratic function f(x) = 6x2 + 12x – 7? x = –1 – and x = –1 + x = –1 – and x = –1 + x = –1 – and x = –1 + x = –1 – and x = –1 +

What are the zeros of the quadratic function f(x)

barbiegirllover

17.01.2022

$x=-1+\frac{\sqrt{78} }{6}$ and

$x=-1-\frac{\sqrt{78} }{6}$

Step-by-step explanation:

f(x) = 6x^2 + 12x - 7

To find out the zeros of the quadratic function, we apply quadratic formula

$x=\frac{-b+-\sqrt{b^2-4ac}}{2a}$

From the given f(x), the value of a=6, b=12, c=-7

Plug in all the values in the formula

$x=\frac{-12+-\sqrt{12^2-4(6)(-7)}}{2(6)}$

$x=\frac{-12+-\sqrt{312}}{2(6)}$

$x=\frac{-12+-2\sqrt{78}}{2(6)}$

Now divide each term by 12

$x=-1+-\frac{\sqrt{78} }{6}$

We will get two values for x

$x=-1+\frac{\sqrt{78} }{6}$ and

$x=-1-\frac{\sqrt{78} }{6}$

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allisonatalie6654

25.06.2022

9(2p-4)

Step-by-step explanation:

To factor an expression, find the GCF of each term. 18p and 36 share in common the factor 9. Divide each term by 9 to get the factor.

18p - 36 = 9(2p-4)

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