Katiecool290
Katiecool290
03.12.2020 • 
Mathematics

What are the zeros of the quadratic function f(x) = 6x2 – 24x + 1? x = –2 + sqrt(1/2) or x = –2 – sqrt(1/2)

x = 2 + sqrt(1/2) or x = 2 – sqrt(1/2)

x = –2 + sqrt(23/6) or x = –2 – sqrt(23/6)

x = 2 + sqrt(23/6) or x = 2 – sqrt(23/6)

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