What happens to the standard error of an estimate when the sample size in SRS decreases?

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potato3999

15.02.2020

Mathematics

$x=-\frac{17}{8}+\frac{\sqrt{97} }{8}$ or $x=-\frac{17}{8}-\frac{\sqrt{97} }{8}$

Step-by-step explanation:

x^2+17x+12=-3x^2

Add 3x^2 on both sides.

x^2+17x+12+3x^2=-3x^2+3x^2

x^2+17x+12+3x^2=0

Combine like terms;

4x^2+17x+12=0

Use the quadratic formula;

a=4

b=17

c=12

$x=\frac{-b\frac{+}{}\sqrt{b^2-4ac} }{2a}$

$x=\frac{-(17)\frac{+}{}\sqrt{(17)^2-4(4)(12)} }{2(4)}$

$x=\frac{-17\frac{+}{}\sqrt{289-192} }{8}$

$x=\frac{-17\frac{+}{}\sqrt{97} }{8}$

$x=-\frac{17}{8}+\frac{\sqrt{97} }{8}$ or $x=-\frac{17}{8}-\frac{\sqrt{97} }{8}$

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