McMingMing

McMingMing

06.01.2021 •

Mathematics

What has the same solution as 8x + 3y = 5
4x + 2y = 3

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Ответ:

neekWYB

30.03.2022

The weights of the package follows a probability density function

The mean is 4.31 and the variance is 51.42, respectively.The average cost of shipping a package is $10.78The probability a package weighs over 59 pounds is 0.0027

The probability density function is given as:

$\mathbf{f(x) = \frac{70}{69x^2},\ 1 < x < 70}$

(a) The mean and the variance

The mean is calculated as:

$\mathbf{E(x) = \int\limits^a_b {x \cdot f(x)} \, dx }$

So, we have:

$\mathbf{E(x) = \int\limits^{70}_1 {x \cdot \frac{70}{69x^2} } \, dx }$

$\mathbf{E(x) = \int\limits^{70}_1 {\frac{70}{69x} } \, dx }$

Rewrite as:

$\mathbf{E(x) = \frac{70}{69}\int\limits^{70}_1 {x^{-1} } \, dx }$

Integrate

$\mathbf{E(x) = \frac{70}{69} {ln(x)}|\limits^{70}_1 } }$

Expand

$\mathbf{E(x) = \frac{70}{69} \cdot {(ln(70) - ln(1)) }}$

$\mathbf{E(x) = 4.31 }}$

The variance is calculated as:

$\mathbf{Var(x) = E(x^2) - (E(x))^2}$

Where:

$\mathbf{E(x^2) = \int\limits^a_b {x^2 \cdot f(x)} \, dx }$

So, we have:

$\mathbf{E(x^2) = \int\limits^{70}_1 {x^2 \cdot \frac{70}{69x^2} } \, dx }$

$\mathbf{E(x^2) = \int\limits^{70}_1 {\frac{70}{69} } \, dx }$

Rewrite as:

$\mathbf{E(x^2) = \frac{70}{69}\int\limits^{70}_1 {1 } \, dx }$

Integrate

$\mathbf{E(x^2) = \frac{70}{69} x|\limits^{70}_1 } }$

Expand

$\mathbf{E(x^2) = \frac{70}{69} \cdot {(70 - 1) }}$

$\mathbf{E(x^2) = 70 }}$

So, we have:

$\mathbf{Var(x) = E(x^2) - (E(x))^2}$

$\mathbf{Var(x) = 70 - 4.31^2}$

$\mathbf{Var(x) = 51.42}$

Hence, the mean is 4.31 and the variance is 51.42, respectively.

(b) The average cost of shipping a package

In (a), we have:

$\mathbf{E(x) = 4.31 }}$ ---- Mean

So, the average cost of shipping a package is:

$\mathbf{Average =4.31 \times 2.50}$

$\mathbf{Average =10.78}$

Hence, the average cost of shipping a package is $10.78

(c) The probability a package weighs over 59 pounds

This is represented as: P(x > 59)

So, we have:

$\mathbf{P(x 59) = P(59 < x < 70)}$

So, we have:

$\mathbf{P(x 59) = \int\limits^{70}_{59} { \frac{70}{69x^2}} \, dx }$

Rewrite as:

$\mathbf{P(x 59) = \frac{70}{69}\int\limits^{70}_{59} { x^{-2}} \, dx }$

Integrate

$\mathbf{P(x 59) = \frac{70}{69} \cdot { -\frac 1x}|\limits^{70}_{59}}$

Expand

$\mathbf{P(x 59) = \frac{70}{69} \cdot (-\frac{1}{70} + \frac{1}{59})}$

$\mathbf{P(x 59) = 0.0027}$

Hence, the probability a package weighs over 59 pounds is 0.0027

Read more about probability density functions at:

link

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