What if you get a chance to fawk these moderators??

hi ankit bhaiya

can u remember me

Given equation : y=5/2x.

Solution: In order to graph direct variation equation, we need to make a table of different values of x and y.

We need to plug some values of x's in equation to get values of y's.

Because, we have fraction 5/2, and 2 in denominator. So it would be better to take multiples of 2, so that we don't get values in decimals.

Let us take x=0 first.

Plugging x=0 in given equation, we get

y=5/2x = 5/2(0) = 0.

Let us take x=2 first.

Plugging x=2 in given equation, we get

y=5/2 *(2) = 5

Let us take x=2 first.

Plugging x=4 in given equation, we get

y=5/2 *(4) = 5 *2 = 10.

We got three coordinates for the graph (0,0) , (2,5) and (4, 10).

Let us plot those coordinates on the graph and join the points to draw a straight line.